Question

Use Hooke's Law, which states that the distance a spring stretches (or compresses) from its natural, or equilibrium, length varies directly as the applied force on the spring. A force of 265 newtons stretches a spring 0.15 meter. (a) What force stretches the spring 0.4 meter

Answer 1

706.68 N

Step-by-step explanation:

By Hooke's law,

`F = ke`

`k=(F)/(e)`

Using the values in the question,

`k=\frac{265\text{ N}}{0.15 \text{ m}}=1766.7\text{ N/m}`

When e = 0.4 m,

`F = 1766.7\text{ N/m}*0.4\text{ m}=706.68\text{ N}`