Question

A sample of 3.785 g of a compound is analyzed, and found to contain 1.302 g Fe and 2.483 g Cl. Another sample of the compound is found to contain 2.329 g of Cl. How many grams of Fe will it contain

Answer 1

Step-by-step explanation:

Defining law of simple multiple proportions, which states that when two or more elements form more than one compound, the ratio of the weights of one element that combine with a given weight of another element in the different compounds is a ratio of small whole numbers

Ratio of Fe and Cl in the first sample is:

Mass of Fe: Mass of Cl

1.302 : 2.483

Ratio = 1 : 1.9

Therefore, in the other sample;

Mass of Fe: Mass of Cl

= 1 : 1.9

= x : 2.329

x = 2.329 ÷ 1.9

= 1.221 g.

Answer 2

1.221g

Step-by-step explanation:

First Sample

Ratio of Fe and Cl is given as;

Mass of Fe: Mass of Cl

1.302g : 2.483g

Second Sample;

Mass of Fe: Mass of Cl

xg : 2.329g

The ratio between both elements is constant in both samples, so we have;

Ratio of first sample = Ratio of second sample

1.302g : 2.483g = xg : 2.329g

1.302 / 2.483 = x / 2.329

x = (2.329 * 1.302) / 2.483

x = 1.221g