The height of the trapezoid = 6 cm
Solution:
The composite figure is splitted into two shapes.
One is rectangle and the other is trapezoid.
Area of the rectangle = length × width
= 12 cm × 8 cm
Area of the rectangle = 96 cm²
Area of the trapezoid =
![(1)/(2) * \text{sum of the parallel side}* \text{height}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bxk8gp6zsloru1vyu5z4k4fgetekw5p833.png)
![$=(1)/(2)* (10 + 12 ) * h](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jsrbemjyvwkhnsi90s8y5a3f714nwtzklr.png)
![$=(1)/(2)* 22 * h](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7hkt3x3daa0km9wu3q2gv7c2jvqsm8ur0r.png)
Area of the trapezoid = 11 h cm²
Area of the composite shape = 162 cm²
⇒ 96 + 11 h = 162
Subtract 96 on both sides of the equation.
⇒ 11 h = 162 – 96
⇒ 11 h = 66
Divide by 11 on both sides of the equation.
⇒ h = 6 cm
The height of the trapezoid = 6 cm