1.50 grams of potassium chloride are produced
Potassium hydroxide is the limiting reactant
Step-by-step explanation:
HCl + KOH→KCl + H₂O
HCl and KOH react on a 1 : 1 mole ratio. They also produce products on a 1 : 1 ratio.
The limiting reagent, in this case, is KOH because it will be fully exhausted in the reaction while the excess HCl will be left remaining.
The remaining HCL will be 2.50 g – 1.50 g
= 1g
Remember because both reactants react at a 1: 1 ratio
In addition, 1.50 g on KCl will be formed in the products