Question

A 0.133 kg hockey puck going 45.2 m/s hits the wall of the ice rink and

rebounds at 27.7 m/s. (a) What is the impulse delivered to the puck? (use
the initial direction of motion as the positive direction)
(b) What is impulse delivered to the wall?
(C) If the wall and puck are in contact for 0.03 s, what is the force on the
puck?

Answer 1

The detailed calculations are shown below:

Step-by-step explanation:

(a) impulse delivered to the puck = m (
`v_(i)` -
`v_{f` )

= 0.133 (45.2 - 27.7)

= 2.327 kgm/s

(b) impulse delivered to the wall = the net impulse on the wall is nearly 0. Technically speaking, this will actually change the rotation of the earth slightly, accounting for this transfer of momentum.

(c) Impulse = force × time

or, 2.327 = force × 0.03

or, force=
`(2.327)/(0.03)`

∴ force = 77.567 N