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Find the equation of a line that passes through the point (4,2) that is perpendicular to the line y=(4/3)x

User Kindagonzo
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Answer:

Explanation:

Hello:

an equation for the line is : y =mx +b (m: is a slope )

perpendicular to the line described by : y = 4/3 x

So : product for two slopes = -1 means : m×4/3=-1

m = -3/4

now : y = -3/4 x+b

but this line :

through the point (4,2) : 2 =(-3/4)(4)+b....... b=5

conclusion :

the equation is : y = -3/4x +5

User Jdinklage Morgoone
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