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5 votes
What volume (in L) of a 6.84 M.

sodium bromide (NaBr) solution
would be needed to make 588 mL of
a 1.84 M solution by dilution?

User Zahmati
by
3.2k points

2 Answers

1 vote

Answer:

0.158 liters

Step-by-step explanation:

User Ludovic C
by
3.5k points
4 votes

Answer:

0.158L

Step-by-step explanation:

From the question, we obtained the following information:

C1 = 6.84 M

V1 =?

C2 = 1.84 M

V2 = 588 mL = 588/1000 = 0.588L

Using the dilution formula C1V1 = C2V2. The original volume can calculated for as follows:

C1V1 = C2V2

6.84 x V1 = 1.84 x 0.588

Divide both side by 6.84

V1 =(1.84 x 0.588) / 6.84

V1 = 0.158L

User Ssayols
by
4.1k points