Question

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MCKEALG9 2.5.001.
of a rectangular lot if the width w is 55 feet and the perimeter P is 290 feet.
Use the formula P = 21 + 2w to find the length
1 =
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MCKEALG9 2.5.015.
Use the equation y = (x + 1)2 - 10 to find the value of y when x is -2.
y =
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Answer 1

If the width w is 55 feet and the perimeter P is 290 feet.

Use the formula P = 21 + 2w to find the length

Solution:

The perimeter of rectangle is given as:

P = 2(length + width)

From given,

length = ?

width = 55 feet

perimeter = 290 feet

Therefore,

290 = 2(length + 55)

`length + 55 = (290)/(2)\\\\length + 55 = 145\\\\length = 145 - 55\\\\length = 90`

Thus length of rectangular lot is 90 feet

Use the equation y = (x + 1)2 - 10 to find the value of y when x is -2

Solution:

Given equation is:

`y = (x + 1)^2 - 10`

To find: y when x = -2

Substitute x = -2

`y = (-2 + 1)^2 -10\\\\y = -1^2 -10\\\\y = 1 - 10\\\\y = -9`

Thus y is -9 when x is -2