Question

If distance between two points A(2,2) and B(x,5) is 5 units find value of x​

Answer 1

X can be - 2 or 6.

Explanation:

d=5

d=sqrt((x2-x1)^2 +(y2-y1)^2)

5=sqrt((x-2)^2 +(5-2)^2)

5^2 =(x-2)^2 +3^2

25=(x-2)^2 +9

(x-2)^2 =25-9

(x-2)^2 =16

x-2=sqrt(16)

x-2=4

x=4+2

x=6;

x-2=-4

x=-4+2

x=-2