Question

The ages of four cousins are consecutive integers. Let the integers equal n, n+1, n+2 and n +3. The sum of their ages is 34 How old is the oldest

cousin?
____ years old​

Answer 1

10

Explanation:

n + n+1 + n+2 + n+3 = 4n + 6

4n + 6 = 34

4n = 28

n = 7

Eldest: n + 3 = 7 + 3 = 10

Answer 2

Ages are: 7, 8, 9 and 10.

The age of the eldest cousin is '10'

Explanation:

Age of four cousins are:

`n`,
`n+1` ,
`n+2` and
`n +3`

Sum of their ages is 34

So,
`n`+(
`n+1` )+(
`n+2`) + (
`n +3`)=34

`n+(n+1)+(n+2)+(n+3)=34\\\\n+n+1+n+2+n+3=34\\\\4n+6=34\\\\4n=34-6\\\\4n=28\\\\n=(28)/(4)\\\\ n=7`

So the ages are:

`n=7\\n+1=7+1=8\\n+2=7+2=9\\n+3=7+3=10\\`

The age of the eldest cousin is '10'