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I am trying to get the radius of this equation.

x²+y²-11y+28=0
The subject is writing equations of circles in standard form using properties.

User Merc
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1 Answer

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Answer:

Explanation:

x^2 + y^2 - 11y + 28 = 0

x^2 + y^2 - 11y + (11/2)^2 = -28 + (11/2)^2

x^2 + (y - 11/2)^2 = 2.25

so, it's a circle with center at (0,5.5) with radius 1.5

User Scott Blasingame
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