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How to solve these two problems ?

How to solve these two problems ?-example-1
User Napoleonss
by
5.1k points

1 Answer

5 votes

8)
\theta is -0.896 radians

9) length of arc is 41.91 cm

Solution:

8)

Given that,


tan\ \theta = (-5)/(4)


\theta is in quadrant 4

To find:
\theta

From given,


tan\ \theta = (-5)/(4)\\\\\theta = tan^(-1) (-5)/(4)\\\\\theta = tan^(-1) (-1.25)\\\\\theta = -51.34

Thus value of
\theta is -51.34 degrees

Convert degrees to radians


-51.34\ degree = -51.34 * ( \pi )/(180)\ radian\\\\-51.34\ degree = -0.896\ radian

Thus
\theta is -0.896 radians

9)

From given,

radius = 15.4 cm


\theta = (13 \pi )/(15)

The length of arc when angle in radians is:


arc\ length = r * \theta\\\\arc\ length = 15.4 * ( 13 \pi )/(15)\\\\arc\ length = 15.4 * 2.721\\\\arc\ length = 41.91

Thus length of arc is 41.91 cm

User Mainajaved
by
5.3k points
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