Question

A regular square pyramid has a height of 6 and a base with sides of length 12. What is the: Lateral area of the pyramid?

Answer 1

347.65

Step-by-step explanation:

`l*w+l√((w/2)^2+5^2+w)+W*√((l/2)^2+h^2)`

Answer 2

Answer: Lateral area of the pyramid is 144

Explanation:

The formula for determining the lateral surface area of a regular pyramid is expressed as

Lateral area = (perimeter of base x slant height of pyramid) /2

From the information given,

Length of base = 12

Since the base is a square, the perimeter of the base is

4L = 4 × 12 = 48

Height of pyramid = 6

Therefore, lateral surface area of the pyramid is

(48 × 6)/2 = 288/2 = 144