Option B
Multiply first equation by -2 and second equation by 3, solution (1, 1)
Solution:
Given system of equations are:
3x - 5y = -2 -------- eqn 1
2x + y = 3 ------- eqn 2
We have to solve the system of equations
Multiply eqn 1 by -2
-6x + 10y = 4 ------- eqn 3
Multiply eqn 2 by 3
6x + 3y = 9 -------- eqn 4
Add eqn 3 and eqn 4
-6x + 10y = 4
6x + 3y = 9
( + ) ------------
13y = 13
y = 1
Substitute y = 1 in eqn 2
2x + 1 = 3
2x = 2
x = 1
Thus solution is (1, 1)
Thus option B is correct