Question:
The difference of two numbers is nine if the larger number is one more than twice the smaller number find a larger number
Answer:
The larger number is 17
Solution:
Let the smaller number be "a"
Let the larger number be "b"
The difference of two numbers is nine
Therefore,
b - a = 9 ------ eqn 1
larger number is one more than twice the smaller number
Therefore,
b = 1 + 2a ----- eqn 2
Substitute eqn 2 in eqn 1
1 + 2a - a = 9
a = 8
Substitute a = 8 in eqn 1
b - 8 = 9
b = 9 + 8
b = 17
Thus the larger number is 17