Question

Fractii.(1supra12+1supra24-1supra36):(1supra4+3supra5)×2antregi3supra7​

Answer 1

`\large\boxed{\large\boxed{(35)/(459)}}`

Step-by-step explanation:

Fractions:

`\bigg((1)/(12)+(1)/(24)-(1)/(36)\bigg):\bigg((1)/(4)+(3)/(5)\bigg)* (2)/(3)`

1. Solve the first parenthesis:

`(1)/(12)+(1)/(24)-(1)/(36)=(6+3-2)/(72)=(7)/(72)`

2. Solve the second parenthesis:

`(1)/(4)+(3)/(5)=(5+12)/(20)=(17)/(20)`

3. Solve the division:

`(7)/(72):(17)/(20)=(7)/(72)* (20)/(17)=\\ \\ \\ =(7* 20)/(72* 17)=(7* 5)/(18* 17)=(35)/(306)`

4. Multiply by the last fraction:

`(35)/(306)* (2)/(3)=(35)/(153* 3)=(35)/(459)`