Fractii.(1supra12+1supra24-1supra36):(1supra4+3supra5)×2antregi3supra7

Question

asked Mar 15, 2021 97.7k views

1 Answer

TPArrow · Answer 1 · 2021-03-19T16:06:03+0000

Answer:

$\large\boxed{\large\boxed{(35)/(459)}}$

Step-by-step explanation:

Fractions:

$\bigg((1)/(12)+(1)/(24)-(1)/(36)\bigg):\bigg((1)/(4)+(3)/(5)\bigg)* (2)/(3)$

1. Solve the first parenthesis:

(1)/(12)+(1)/(24)-(1)/(36)=(6+3-2)/(72)=(7)/(72)

2. Solve the second parenthesis:

(1)/(4)+(3)/(5)=(5+12)/(20)=(17)/(20)

3. Solve the division:

$(7)/(72):(17)/(20)=(7)/(72)* (20)/(17)=\\ \\ \\ =(7* 20)/(72* 17)=(7* 5)/(18* 17)=(35)/(306)$

4. Multiply by the last fraction:

(35)/(306)* (2)/(3)=(35)/(153* 3)=(35)/(459)