Option B:
is the interval in which
has a real zero
Step-by-step explanation:
The given equation is
We need to determine x at which the value of f(x) becomes zero.
Option A:
![-1<x<0 ; 0<x<1 ; 1<x<2 ; 2<x<3](https://img.qammunity.org/2021/formulas/mathematics/high-school/pzdzdjuegozfqtqn1vx3pro8wqanbxoby9.png)
Let us substitute the values of x in the equation f(x), we get,
(i) Consider the 1st interval
![-1<x<0](https://img.qammunity.org/2021/formulas/mathematics/high-school/zqh9og4yh8fkecpcddkuw3r8rdnss7cng6.png)
![f(-1)=3 (-1)-5 (1)+5(-1)+7=-6](https://img.qammunity.org/2021/formulas/mathematics/high-school/fcbnno7kibf8m73vc2qkffqc8pye0nrvoy.png)
![f(0)=3 (0)-5 (0)+5(0)+7=7](https://img.qammunity.org/2021/formulas/mathematics/high-school/tyraidztzbvlfbnm3v38hruiyx0ciaczxy.png)
Since, there is a change of sign between the two interval, f(x) has a zero between the interval
![-1<x<0](https://img.qammunity.org/2021/formulas/mathematics/high-school/zqh9og4yh8fkecpcddkuw3r8rdnss7cng6.png)
(ii) Consider the 2nd interval
![0<x<1](https://img.qammunity.org/2021/formulas/mathematics/college/zobbc246u3avkjlvp89jhec7fuvlkejmh5.png)
![f(0)=3 (0)-5 (0)+5(0)+7=7](https://img.qammunity.org/2021/formulas/mathematics/high-school/tyraidztzbvlfbnm3v38hruiyx0ciaczxy.png)
![f(1)=3 (1)-5 (1)+5(1)+7=10](https://img.qammunity.org/2021/formulas/mathematics/high-school/m1540um2guyu7pyn404yc0x6vupid7mkpg.png)
Since, there is no change of sign between the two interval, f(x) does not have a zero between the interval
![0<x<1](https://img.qammunity.org/2021/formulas/mathematics/college/zobbc246u3avkjlvp89jhec7fuvlkejmh5.png)
(iii) Consider the 3rd interval
![1<x<2](https://img.qammunity.org/2021/formulas/mathematics/high-school/d74n8encfjfh1ozgo5qifoun0lqw0vhujm.png)
![f(1)=3 (1)-5 (1)+5(1)+7=10](https://img.qammunity.org/2021/formulas/mathematics/high-school/m1540um2guyu7pyn404yc0x6vupid7mkpg.png)
![f(2)=3 (8)-5 (4)+5(2)+7=21](https://img.qammunity.org/2021/formulas/mathematics/high-school/uvbbypaxn0qlp8sfn2r6pdwu0jpddu5lvx.png)
Since, there is no change of sign between the two interval, f(x) does not have a zero between the interval
![1<x<2](https://img.qammunity.org/2021/formulas/mathematics/high-school/d74n8encfjfh1ozgo5qifoun0lqw0vhujm.png)
(iv) Consider the 4th interval
![2<x<3](https://img.qammunity.org/2021/formulas/mathematics/high-school/eeme8ob9n30ym75zu68bfn3qyl9ma8je3j.png)
![f(2)=3 (8)-5 (4)+5(2)+7=21](https://img.qammunity.org/2021/formulas/mathematics/high-school/uvbbypaxn0qlp8sfn2r6pdwu0jpddu5lvx.png)
![f(3)=3 (27)-5 (9)+5(3)+7=58](https://img.qammunity.org/2021/formulas/mathematics/high-school/elr1hhn0ah7zxvnlucnm2yvkf5665opeqm.png)
Since, there is no change of sign between the two interval, f(x) does not have a zero between the interval
![2<x<3](https://img.qammunity.org/2021/formulas/mathematics/high-school/eeme8ob9n30ym75zu68bfn3qyl9ma8je3j.png)
From all the above 4 options, there is no change of sign between the intervals and hence, Option A is not the correct answer.
Option B:
![-1<x<0](https://img.qammunity.org/2021/formulas/mathematics/high-school/zqh9og4yh8fkecpcddkuw3r8rdnss7cng6.png)
Let us substitute the values of x in the equation f(x), we get,
![f(-1)=3 (-1)-5 (1)+5(-1)+7=-6](https://img.qammunity.org/2021/formulas/mathematics/high-school/fcbnno7kibf8m73vc2qkffqc8pye0nrvoy.png)
![f(0)=3 (0)-5 (0)+5(0)+7=7](https://img.qammunity.org/2021/formulas/mathematics/high-school/tyraidztzbvlfbnm3v38hruiyx0ciaczxy.png)
Since, there is a change of sign between the two interval, f(x) has a zero between the interval
![-1<x<0](https://img.qammunity.org/2021/formulas/mathematics/high-school/zqh9og4yh8fkecpcddkuw3r8rdnss7cng6.png)
Hence, Option B is the correct answer.
Option C:
![1<x<2](https://img.qammunity.org/2021/formulas/mathematics/high-school/d74n8encfjfh1ozgo5qifoun0lqw0vhujm.png)
Let us substitute the values of x in the equation f(x), we get,
![f(1)=3 (1)-5 (1)+5(1)+7=10](https://img.qammunity.org/2021/formulas/mathematics/high-school/m1540um2guyu7pyn404yc0x6vupid7mkpg.png)
![f(2)=3 (8)-5 (4)+5(2)+7=21](https://img.qammunity.org/2021/formulas/mathematics/high-school/uvbbypaxn0qlp8sfn2r6pdwu0jpddu5lvx.png)
Since, there is no change of sign between the two interval, f(x) does not have a zero between the interval
![1<x<2](https://img.qammunity.org/2021/formulas/mathematics/high-school/d74n8encfjfh1ozgo5qifoun0lqw0vhujm.png)
Hence, Option C is not the correct answer.
Option D:
![-8<x<-7](https://img.qammunity.org/2021/formulas/mathematics/high-school/bm8g02uok6hn623pkpewmd6e0quiiz4bdc.png)
Let us substitute the values of x in the equation f(x), we get,
![f(-8)=3 (-512)-5 (64)+5(-8)+7=-1889](https://img.qammunity.org/2021/formulas/mathematics/high-school/ajf3qw187i2xosyovv9zmva0z6c9gatli4.png)
![f(-7)=3 (-343)-5 (49)+5(-7)+7=-1302](https://img.qammunity.org/2021/formulas/mathematics/high-school/l2n3raakixjoglb774ue417t232hhemzdj.png)
Since, there is no change of sign between the two interval, f(x) does not have a zero between the interval
![-8<x<-7](https://img.qammunity.org/2021/formulas/mathematics/high-school/bm8g02uok6hn623pkpewmd6e0quiiz4bdc.png)
Hence, Option D is not the correct answer.