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Sin2A + sin2B - sin2C = 4cosA×cosB×cosC​
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Sin2A + sin2B - sin2C = 4cosA×cosB×cosC​

Sin2A + sin2B - sin2C = 4cosA×cosB×cosC​-example-1
User Dieworld
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2 Answers

2 votes

Answer:

use sin2A as 2sinAcosA and solve

User Kiran RS
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4.9k points
0 votes

Answer:

Inconclusive

Step-by-step explanation:

Sin2A= Sin(A+A)= SinACosA + CosAsinA=2SinACosA

Similarly

Sin2B= 2SinBCosB

Sin2C=2SinCCosC

Adding all; we cannot arrive at the expression at the right.

User TypingPanda
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