Answer:
The largest rectangular space is
![24m^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/xby8mhtmbtwyinnhsqoy3ufmrgaufqu7tv.png)
Explanation:
Given a 20m long wire fence, implies that the perimeter of the fence has been given, because Perimeter can be defined as the length of the boundary of a figure (in this case, a rectangle)
So, from the formula: Perimeter = 2 (L + B) =
![20m^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/q1piprwt3crr6oots1pj1lx254lu2dzmns.png)
We have that L + B =
![10m^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/9cmjcden2d2l8qukofa5515j9ofuqy2863.png)
The possible values of L and B are:
(L, B) = (9, 1), (8, 2), (7, 3) and (6, 4).
The areas of the rectangle that will be formed using these values are respectively;
,
,
and
, the largest area of which is the last which corresponds to the values (6, 4).
The largest rectangular space that the gardener can enclose is therefore
![24m^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/xby8mhtmbtwyinnhsqoy3ufmrgaufqu7tv.png)