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A rectangular phone is 3 cm longer than it is wide. The photo is surrounded with a wooden frame that is 2cm wide on all sides. The area of the frame is 52 square centimeters. Find the dimensions of the photo.

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Answer:

the width is 3.9

the length is 3+w= 3+3.9 =6.9

Explanation:

A photo is rectangular with 3cm longer than its width

meaning length is 3+w(3 plus the dimension of the width)

area = length x breadth = (3+w)w=3w+w²=w²+3w

A frame housing the photo is 2cm wide on all sides

meaning the length is 3+w+2

the width is w+2

area of the frame is 52cm²

area of frame = length x breadth

area of frame= (3+w+2) * (w+2)

area of frame = (5+w)x(w+2) =w(5+w)+2(5+w)= 5w+w²+10+2w

area of frame= 5w+2w+w²+10= 7w +w²+10=w²+7w+10

area of frame= w²+7w+10

52 = w²+7w+10

w²+7w+10-52=0

w²+7w-42=0

using quadratic formula

x=-b±√b2-4ac/2a

b= 7

c=-42

a=1

x= -7±√7²-4(1)(-42)/2(1) = -7±√49+168/2

x=-7±√217/2= -7±14.7309198627/2

x= -7+14.73/2 x= -7-14.73/2

x=7.73/2 -21.73/2

x= 3.865, -10.865

since a dimension can not be negative e neglect the negative sign

x=3.9

the width is 3.9

the length is 3+w= 3+3.9 =6.9

User Tomasz Szymulewski
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