Answer:
D) 0.8247
Explanation:
The first thing is to look for a normal distribution table that gives us the values of Z.
Now the percentage of people with BMI between 25 and 30 is given as follows:
P (25 <x <30) = P {[(25 -28.4) /1.6] <Z <P {[(30 -28.4) /1.6]
The value of 25 would be 25 minus the arithmetic mean divided by the standard deviation.
The value of 30 would be 30 minus the arithmetic mean divided by the standard deviation.
When solving that we have the following way:
P {-2.125 <Z <1]
This can be expressed as follows:
P (Z <1) - [1 - P (Z <2.13)]
Now we turn to the normal distribution table and find that:
P (Z <1) = in table 0.8413
P (Z <2.13) = in table 0.9834
When replacing the values we have that:
0.8413 - (1 - 0.9834) = 0.8247
Which means that the percentage of person with that BMI is 0.8247