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Approximately one out of every 2,500 Caucasians in the United States is born with the recessive genetic disorder cystic fibrosis. According to the Hardy-Weinberg equilibrium equation, approximately how many people are carriers

User Xenethyl
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2 Answers

3 votes

Answer:

1 in 25 = 4%

Step-by-step explanation:

User Alex Efremov
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4 votes

Answer:

4% of the white population in the US are carriers of cystic fibrosis.

Step-by-step explanation:

According to the Hardy-Weinberg equilibrium equation, if q2 equals 1/2,500, then q equals .02, p equals .98, and 2pq equals approximately .04, or 4%.

Remember that the Hardy-Weinberg equilibrium equation is used when the population maintains its genetic variation constant.

User Manuel Temple
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