Question

F(x)= -2x^2
what is the vertex of this and/or how do you find the vertex??​

Answer 1

(0,0)

Explanation:

x value of vertex = -b/2a

ax^2+bx+c

-2x^2+0x+0 sinc you have no value of b & c in your quadratic function

-b = 0

2a = (2)(-2)

-b/2a = (0/-4) = 0

x value of the vertex = 0

plug 0 in for all values of x in the function to find y coordinate value

-2(0)^2 = 0

(x,y) = (0,0)