Question

Assume that charge −q is placed on the top plate, and +q is placed on the bottom plate. What is the magnitude of the electric field E between the plates? Express E in terms of q and other quantities given in the introduction, in addition to ϵ0 and any other constants needed..

Answer 1

`E=(q)/(\epsilon_oA)`

Step-by-step explanation:

Let the area of each plate be A.

From Gauss Law,

`\phi=(q)/(\epsilon_o)`

`\phi=E.A`

`\Rightarrow E.A=(q)/(\epsilon_o)\\\Rightarrow E=(q)/(\epsilon_oA)`

Thus, using Gauss law, electric field between the plates is:

`E=(q)/(\epsilon_oA)`