Answer:
1.
![d)y=x^2+2](https://img.qammunity.org/2021/formulas/mathematics/high-school/xoybzubd54b3p3eg5drkt6iu41728goysf.png)
2.
![b)y=2x^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/kvipawbkrligp0eqd5q0j4ydzwc0ysv623.png)
3.
![c)y=-x^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/edp68pdxf4qkjyq78q4yvy5f4g89mbtodm.png)
4.
![c)y=(1)/(2)x^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/3f37et5sm22qbdbd7hxej3aqkl2evpeta1.png)
Step-by-step explanation:
1. Start with the pair (0,2)
Just because it is quick to substitute x = 0 mentally and get the answer by inspection. You will quickly notices that a), b) and c) do not match:
![a)y=2x^2=2(0)^2=2(0)=0\implies (0,0)wrong](https://img.qammunity.org/2021/formulas/mathematics/high-school/844s6k3ywo2linwq8o8zmuwjonigtz085v.png)
![b)y=(x-3)^2=(0-3)^2=(-3)^2=9\implies (0,9)wrong](https://img.qammunity.org/2021/formulas/mathematics/high-school/n6ujm2sb02inkqy834mqtcq0nhbr7b8e7x.png)
![c)y=x^2-3=(0)^2-3=0-3=-3\implies (0,-3)wrong](https://img.qammunity.org/2021/formulas/mathematics/high-school/dxekvzs5d4rlgty3miltycjlthhq4ws1s7.png)
![d)y=x^2+2=(0)^2+2=0+2=2\implies (0,2)\checkmark](https://img.qammunity.org/2021/formulas/mathematics/high-school/bby1vlic8e2noese88nvxwp3qrf1hxutxl.png)
Thus, the answer is d)
2. Try b) y = 2x² for every point
![(2,8)\implies x=2\implies y=2(2)^2=8\checkmark\\\\(-2,8)\implies x=-2\implies y=2(-2)^2=8\checkmark\\\\(4,3)\implies x=4\implies y=2(4)^2=32\checkmark\\\\(-3,18)\implies x=-3\implies y=2(-3)^2=18\checkmark](https://img.qammunity.org/2021/formulas/mathematics/high-school/di0dogva7b2a4qccpo1rk5qtwrb3aik74l.png)
Thus, b) y=2x² is the correct equation.
3. Since every y is negative the only possible answer is c) y = -x²
Proove it:
![x=4\implies y=-(4)^2=-16\checkmark\\\\x=-4\imples y=-(-4)^2=-16\checkmark\\\\x=3\implies y=-(3)^2=-9\checkmark\\\\x=-3\impliesy=-(-3)^2=-9\checkmark](https://img.qammunity.org/2021/formulas/mathematics/high-school/4qw2vdesqqf1djmjgrevh9dk8jj47gm736.png)
4. Try c) y = (1/2)x²
![(4,8)\implies x=4\implies y=(1)/(2) (4)^2=8\checkmark\\ \\ (2,2)\implies x=2\implies y=(1)/(2) (2)^2=2\checkmark\\\\(6,18)\implies x=6\implies y=(1)/(2) (6)^2=18\checkmark\\ \\ (-4,8)\implies x=-4\implies y=(1)/(2) (-4)^2=8\checkmark](https://img.qammunity.org/2021/formulas/mathematics/high-school/kfls0eghdwemf4bth78gp839yih8157eej.png)
Thus, c) y = (1/2)x²