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Write the ion-product expression at equilibrium for each compound: How to enter the correct answer: e.g. silver sulfate (Ag2SO4) enter this: {Ag+}2{SO42-} don't enter spaces, use square brackets [] not {} or () for concentration and don't worry about subscripting or superscripting [ (1) magnesium carbonate (2) calcium phosphate (3) silver sulfide

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Answer:

(1) Magnesium carbonate :-


Q_(MgCO_3)=[Mg^(2+)][CO_3^(2-)]

(2) Calcium phosphate :-


Q_(Ca_3(PO_4)_2)=[Ca^(2+)^3][PO_4^(3-)^2]

(3) Silver sulfide :-


Q_(Ag_2S)=[Ag^(+)^2][S^(2-)]

Step-by-step explanation:

(1) Magnesium carbonate will dissociate as:-


MgCO_3\rightarrow Mg^(2+)+CO_3^(2-)

The expression for the ion-product is as follows:-


Q_(MgCO_3)=[Mg^(2+)][CO_3^(2-)]

(2) Calcium phosphate will dissociate as:-


Ca_3(PO_4)_2\rightarrow 3Ca^(2+)+2PO_4^(3-)

The expression for the ion-product is as follows:-


Q_(Ca_3(PO_4)_2)=[Ca^(2+)^3][PO_4^(3-)^2]

(3) Silver sulfide will dissociate as:-


Ag_2S\rightarrow 2Ag^(+)+S^(2-)

The expression for the ion-product is as follows:-


Q_(Ag_2S)=[Ag^(+)^2][S^(2-)]

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