Question

F(x)=x² + 6x-11
Write the equation in vertex form.

Answer 1

`f(x)=(x+3)^(2)-20`

Explanation:

we have

`f(x)=x^(2)+6x-11`

To convert to vertex form complete the square

`f(x)=(x^(2)+6x+3^2)-11-3^2`

`f(x)=(x^(2)+6x+9)-20`

Rewrite as perfect squares

`f(x)=(x+3)^(2)-20` ----> equation in vertex form

The vertex is the point (-3,-20) (is a minimum)