Yes, since p of 0.037 is less than 0.05, reject the null. Claim is alternative, so is supported
Explanation:
Sample size = 16
S = 7.3
Significance level ( ∝) =0.05
: µ = 6
: µ > 6
The sample size n < 30 and the standard population deviation is uncertain, we will be using one t-test
Test Statistic :
Finding the p value,
P value = 0.0371