Answer:
The area of enlarged prism is 4 times surface area of original prism.
Explanation:
We have been given that a rectangular prism has a height of 8 cm, a length of 4 cm, and a width of 3 cm. The prism is enlarged by a scale of 2.
Let us find total surface area of original prism as:
![SA_1=2(lw+wh+hl)](https://img.qammunity.org/2021/formulas/mathematics/high-school/4o4n7kapdjdgsikcibb3dv28w1nzyknohu.png)
![SA_1=2(4\text{ cm}(3\text{ cm})+3\text{ cm}(8\text{ cm})+8\text{ cm}(4\text{ cm}))](https://img.qammunity.org/2021/formulas/mathematics/high-school/sqratzot496ph6r04445esaudbxyvaa3id.png)
![SA_1=2(12\text{ cm}^2+24\text{ cm}^2+32\text{ cm}^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/i8lm8gmag01nm0stxkw3yjakle9zv9qc2o.png)
![SA_1=2(68\text{ cm}^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/bseasc8wiw5t1sk4vwua739xd8g2rilmdh.png)
![SA_1=136\text{ cm}^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/8dus2bdc090pg45ydk7qegyuawpw8flk42.png)
Since the prism is enlarged by a scale of 2, so each side of new prism would be 2 times grater than side of original prism as:
Length: 8 cm
Width: 6 cm,
Height: 16 cm.
![SA_2=2(48\text{ cm}^2+96\text{ cm}^2+128\text{ cm}^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/oe8e6vswypx2argfahss0j385v95or2huj.png)
![SA_2=2(272\text{ cm}^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/etnj6bxo4yrvnk51trm2uuzvbtgt3ssge1.png)
![SA_2=544\text{ cm}^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/91nvsvtu2ymyjjvjl3e9yj2gcevv8xycrg.png)
Let us find ratio of surface area of the enlarged prism to the original prism as:
![(SA_2)/(SA_1)=(544)/(136)](https://img.qammunity.org/2021/formulas/mathematics/high-school/w2f0uvus7s463x7xx4kt6ez9lw1qzmurec.png)
![(SA_2)/(SA_1)=(4)/(1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/gcj3acdsjwk5bnka292wj7qr9pfy6mch95.png)
Therefore, the area of enlarged prism is 4 times surface area of original prism.