Answer:
The enthalpy change is 10.1 J/g.
Step-by-step explanation:
∆H = Cp(T2 - T1)
∆H is the enthalpy change of air
T2 is the final temperature of air = 35 °C = 35+273 = 308 K
T1 is the initial temperature of air 25 °C = 25+273 = 298 K
Cp is the specific heat at constant pressure at and surrounding 300 K (T2 and T1 surrounds 300 K) = 1.005 J/gK
∆H = 1.005(308 - 298) = 1.005×10 = 10.05 = 10.1 J/g
∆H = 10.1 J/g (in one decimal place)