Question

A photovoltaic array of (solar cells) is 10.0% efficient in gathering solar energy and converting it to electricity. If the average intensity of sunlight on one day is 700 W/m2, what area (in m2) should your array have to gather energy at the rate of 170 W?

Answer 1

Step-by-step explanation:

Given:

Power = 170 W

Power intensity = 700 W/m^2

Formula:

Power intensity = power/area

Area = 170/700

= 0.243 m^2.

Answer 2

`A_(area)=0.243m^(2)`

Step-by-step explanation:

Given data

Average intensity of sunlight on one day I=700 W/m²

Power P=170 W

To find

Area A

Solution

As we know that:

`I_(intensity)=(P_(power))/(A_(area))\\ A_(area)=(P_(power))/(I_(intensity)) \\ A_(area)=(170W)/(700W/m^(2) ) \\ A_(area)=0.243m^(2)`