Question

Ionization energy is the energy needed to eject an electron from an atom or ion. Calculate the ionization energy, I E , of the one‑electron ion He + . The electron starts in the lowest energy level, n = 1 .

Answer 1

Ionization energy of
`He^+` is 54.4 eV.

Step-by-step explanation:

`E_n=-13.6* (Z^2)/(n^2)eV`

where,

`E_n` = energy of orbit

n = number of orbit

Z = atomic number

Energy of n = 1 in an hydrogen like atom:

`E_1=-13.6* (2^2)/(1^2)eV=-54.4 eV`

Energy of n = ∞ in an hydrogen like atom:

`E_(\infty )=-13.6* (2^2)/(\infty ^2)eV=0`

Ionization energy of
`He^+` =

`E=E_(\infty )=E_1=0 - (-54.4 eV)=54.4 eV`