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A chemistry teacher adds 50.0 mL of 1.50 M H2SO4 solution to 200 mL of water. What is the concentration of the final solution?

Use M subscript i V subscript i equals M subscript f V subscript f..
0.300 M
0.375 M
6.00 M
7.50 M

2 Answers

3 votes

Answer:

a on edge

Step-by-step explanation:

User Kulan
by
8.2k points
1 vote

Answer:


Concentration=0.300M

Step-by-step explanation:

This question tests for concentration after dilution of the solution.
50.0mL \ of 1.50M \ H_2SO_4 is added to 200ml of water.

The formula for concentration correlation is given as
c_1v_1=c_2v_2, where the latter relates to the final solution mix.


Concentration=(Moles)/(Volume)\\=(50*10^(-3)L*1.50molL^(-1))/(50*200*10^(-3)L)\\=0.30mol.L^(-1)\\

Therefore the concentration is 0.300M

User Joyson Rego
by
8.6k points

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