Question

Charlie pulls horizontally to the right on a wagon with a force of 37.2 N. Sara pulls horizontally to the left with a force of 22.4 N. How much combined work is done on the wagon after it has moved 2.50 meters to the right?

Answer 1

Step-by-step explanation:

Rightwards force, F1 = 37.2 N

Leftwards force, F2 = 22.4 N

distance, d = 2.5 m

Net force, F = F1 - F2

F = 37.2 - 22.4

F = 14.8 N rightwards

Work done, W = force x distance

W = 14.8 x 2.5

W = 37 J

Answer 2

The work done on the wagon is 37 joules.

Step-by-step explanation:

Given that,

The force applied by Charlie to the right, F = 37.2 N

The force applied by Sara to the left, F' = 22.4 N

We need to find the work done on the wagon after it has moved 2.50 meters to the right. The net force acting on the wagon is :

`F_n=F-F'`

`F_n=37.2-22.4`

`F_n=14.8\ N`

Work done on the wagon is given by the product of net force and displacement. It is given by :

`W=F_n* d`

`W=14.8\ N* 2.5\ m`

W = 37 Joules

So, the work done on the wagon is 37 joules. Hence, this is the required solution.