Answer:
Explanation:
x³-6x²+11x-6
put x=1
1³-6×1²+11×1-6=1-6=11-6=0
by synthetic division
1| 1 -6 11 -6
| 1 -5 6
|----------------
| 1 -5 6 |0
x²-5x+6=0
x²-2x-3x+6=0
x(x-2)-3(x-2)=0
(x-2)(x-3)=0
x=1
x-1=0
so x³-6x²+11x-6=(x-1)(x-2)(x-3)
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