Question

Let's consider a jar consists of 20 marbles. 12 are red and 8 are green. John picked 2 marbles at random. What is the probability that John picked both the marbles red assuming that the first one is not replaced?

Answer 1

Answer:
`\bold{(33)/(95)}`

Explanation:

First pick and Second pick = Probability

`(12\ red)/(20\ total)\quad *`
`(11\ red\ remaining)/(19\ total\ remaining)\\`
`=(132)/(380)\\`

Simplify:

`(132)/(380)/ (4)/(4)=\large\boxed{(33)/(95)}\\`