Question

Water towers store water above the level of consumers for times of heavy use, eliminating the need for high-speed pumps. How high above a user must the water level be to create a gauge pressure of 3.00 x 10^5 Pa?

Answer 1

Belive the answer to your question is 30.6

got it right on the test

Answer 2

`h=305.8103\ m`

Step-by-step explanation:

Given:

• gauge pressure desired,
  `P_g=3* 10^5\ Pa`

As we know that the layers of the liquid column exert pressure due to their weight which is given as:

`P=\rho.g.h`

where:

`P=` pressure due to liquid column

`\rho=` density of the liquid
`=1000\ kg.m^(-3)` for water

`g=` acceleration due to gravity

`h=` height of the liquid column

Similarly:

`P_g=\rho.g.h`

`3* 10^(6)=1000* 9.81* h`

`h=305.8103\ m`