Question

To place an ad in the Harrisonburg newspaper it cost $100 for each 1/8 of a page used. How much would an advertisement cost if it took up 3/4 of a page

Answer 1

Answer: the cost of an advertisement that takes up 3/4 of a page is $600

Explanation:

To place an advertisement in the Harrisonburg newspaper it cost $100 for each 1/8 of a page used. This means that the cost of placing an advertisement of 1 page in the Harrisonburg newspaper would be

1/8 × 100 = $800

Therefore, if an advertisement takes up 3/4 of a page, it means that cost of the advertisement would be

3/4 × 800 = 0.75 × 800 = $600

Answer 2

It would cost $600 for an advertisement of
`(3)/(4)` of a page.

Explanation:

Given:

To place an ad in the Harrisonburg newspaper it cost $100 for each 1/8 of a page used.

Now, to find the cost of an advertisement 3/4 of a page.

So, to get the cost we use unitary method:

If,
`(1)/(8)` of a page used cost = $100.

Then, 1 page used cost =
`100/ (1)/(8)` =
`\$800.`

Thus,
`(3)/(4)` of a page used cost =
`800* (3)/(4) =(2400)/(4)=\$600.`

Therefore, it would cost $600 for an advertisement of
`(3)/(4)` of a page.