Question

In Mega Millions, a South Carolina lottery game, a player selects 5 different numbers from 1 to 56, inclusive, and a Megaball number from 1 to 46, inclusive. In how many ways can these numbers be selected?

Answer 1

2.36153*10^10 possibilities

Explanation:

Given:

- 5 Different number selected from 1 - 56

- 1 number selected from 1 - 46

Find:

In how many ways can these numbers be selected?

Solution:

- The number of ways to select 5 different numbers from range 1 - 56:

_ _ _ _ _

57*56*55*54*53 = 502,452,720 possibilities

- The number of ways to select 1 numbers from range 1 - 46:

47 possibilities.

- The number of possibilities for the entire lottery game:

47 * 502,452,720 = 2.36153*10^10 possibilities