Question

A heavy ball with mass 10 kg is hung from the ceiling of Stolkin Auditorium on a rope of length 4.5 m. It is pulled to one side and released, swinging like a pendulum; at its lowest point, it reaches a speed of 6 m/s. What is the tension in the rope at that point?

Answer 1

Step-by-step explanation:

The given data is as follows.

mass = 10 kg, length = 4.5 m

speed (v) = 6 m/s

Now, formula to calculate tension is as follows.

T =
`mg + (mv^(2))/(r)`

Putting the given values into the above formula as follows.

T =
`mg + (mv^(2))/(r)` (here r = l)

=
`10 * 9.8 + (10 * (6)^(2))/(4.5)`

= (98 + 80) N

= 178 N

Thus, we can conclude that tension in the rope at that point is 178 N.