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IXL geometry help please!

IXL geometry help please!-example-1

1 Answer

2 votes

Answer: 104 degrees

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Work Shown:

Inscribed angle theorem

arc measure = 2*(inscribed angle)

arc BCD = 2*(angle A)

arc BCD = 2*(97)

arc BCD = 194 degrees

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Break arc BCD into its smaller pieces

arc BCD = (minor arc BC) + (minor arc CD)

194 = (90) + (minor arc CD)

194-90 = minor arc CD

104 = minor arc CD

minor arc CD = 104 degrees

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