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Find the x-intercepts of the graph of y=x^2+4x-45

1 Answer

1 vote

Answer:

(-9, 0) (5, 0)

Explanation:

if we set y to 0, then we get:

0 =
x^(2) + 4x - 45

Now, we have to find what the x value is to equal 0.

0 =
-9^(2) + 4(-9) - 45

0 = 81 - 36 - 45

0 = 45 - 45

0 =
5^(2) + 4(5) - 45

0 = 25 + 20 - 45

0 = 45 - 45

User Ali Ashraf
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