Question

Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2, and the profit on every wrap is $3. Sal made a profit of $1,470 from lunch specials last month. The equation 2x + 3y = 1,470 represents Sal's profits last month, where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold. Describe how you would graph this line using the slope-intercept method. Be sure to write using complete sentences.

Answer 1

1) the y intercept is 490 and the slope is -2/3x

2.) First, I would find the point (0,490) and plot a point there. Then I would use our slope -2/3 to figure out what direction and what angle the line goes by counting 2 down and 3 to the right

3.) f(x)= -2/3x+490

The graph represents how many wraps could've been sold for each number of sandwich sales to keep the same profit of $1,470.

4.) graph down below

5.) the profits are the same (slope) but the y intercept is higher then the original graph.

6.) y=-2/3x+300

Explanation:

some of these are part of the problem as well.

1.) 2x+3y=1,470

3y=-2x+1,470

-2x+1,470/3

-2/3x + 490

y=-2/3x + 490

the y intercept is 490 and the slope is -2/3x

2.) First, I would find the point (0,490) and plot a point there. Then I would use our slope -2/3 to figure out what direction and what angle the line goes by counting 2 down and 3 to the right

3.) f(x)= -2/3x+490

The graph represents how many wraps could've been sold for each number of sandwich sales to keep the same profit of $1,470.

5.) 2x+3y=1,593

3y=-2x+1,593

y=-2/3x+531

the profits are the same (slope) but the y intercept is higher then the original graph.

6.) (150, 200) (300, 100)

y intercept= 300

m= 100-200/300-150 = -100/150 = -2/3

y=-2/3x+300

this was a question from a while ago but I thought I would answer it anyways, hope its right and hope it helps you! <3