Question

Xue Ying had 143 more sweets than Joanne.After Joanne gave away 22 sweets, Xue Ying had 6 times as many sweets as Joanne. How many sweets did Joanne have in the end?

Answer 1

In the end Joanne had 55 sweets.

Explanation:

Let the number of sweets that Xue Ying had be y and let the number of sweets Joanne had be x.

It is given that Xue Ying had 143 more sweets than Joanne. We can write this information as an equation.

y = x + 143.

It is also given that Joanne gave away 22 of her sweets and after that Xue Ying had 6 times as many more sweets. We can write this as an equation.

y = 6(x - 22) = 6x - 132.

Therefore we can equate the two equations and solve for x.

x + 143 = 6x - 132

5x = 275

∴ x =
`(275)/(5) = 55` sweets.

Therefore in the end Joanne had 55 sweets.