Question

an op amp in unity gain configuration (buffer) with slew rate of 5v/us is used to amplify a sinusoidal signal with a frequency of 100khz what is the maximum amplitude that the output signal can have without distortion due to slew rate limitation?

Answer 1

The maximum amplitude (
`V_(max)`) will be 7.96 V.

Step-by-step explanation:

We know, for distortion free operation, the slew rate (S) of an OPAMP is written as

`S = 2 \pi f V_(max)`

where '
`f`' is the highest frequency signal.

Therefore, from the above equation we can write,

`&&5 (V)/(\mu s) = 2 \pi 100 kHz * V_(max)\\&or,& V_(max) = (5V)/(10^(-6) s * 2 \pi 100 * 10^(3) Hz)\\&or,& V_(max) = (5)/(2 \pi * 10^(-1)) V = 7.96 V`