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An electron traveling through a wire in an electric circuit experiences a constant force of 4 multiply 10-19 N, always in the direction of its motion. How much work is done on the electron by this force as it travels through 0.8 m of the wire?

1 Answer

5 votes

Answer:

The work done on the electron by this force is
3.2*10^(-19)\ J

Step-by-step explanation:

Given that,

Force
F=4*10^(-19)\ N

distance = 0.8 m

We need to calculate the work done on the electron by this force

Using formula of work done


W=F* d

Where, F = force

d = distance

Put the value into the formula


W=4*10^(-19)*0.8


W=3.2*10^(-19)\ J

Hence, The work done on the electron by this force is
3.2*10^(-19)\ J

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