Question

From a point, 50 feet from the base of a building, the angle of elevation from ground level to the top of the building is 66°. find the height of the building to the nearest hundredth of a foot

Answer 1

112.30 ft

Explanation:

The geometry can be modeled by a right triangle with a base of 50 ft, an angle adjacent to the base of 66°, and a side opposite the angle that is the height of the building. The relationship between these measures is given by the trig function ...

Tan = Opposite/Adjacent

tan(66°) = height/(50 ft)

Solving for the height gives ...

height = (50 ft)tan(66°) ≈ 112.30 ft

The height of the building is about 112.30 feet.