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Light passes through a diffraction grating with a slit spacing of 0.001 mm. A viewing screen is 100 cm behind the grating.

If the light is blue, with a wavelength of 450 , at about what distance from the center of the interference pattern will the first-order maximum appear?

User Fad
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1 Answer

4 votes

Answer:

The distance from the center of the interference pattern will the first-order maximum appear is 50.38 cm.

Step-by-step explanation:

Given that,

Slit space= 0.001 mm

Distance = 100 cm

Wavelength = 450 nm

We need to calculate the angle

Using formula for diffraction maxima

For first order,


d\sin\theta=m\lambda


\theta=\sin^(-1)((\lambda)/(d))

Put the value into the formula


\theta=\sin^(-1)((450*10^(-9))/(0.001*10^(-3)))


\theta=26.74^(\circ)

We need to calculate the distance from the center of the interference pattern will the first-order maximum appear

Using formula of distance


y=D\tan\theta

Put the value into the formula


y=100\tan26.74


y=50.38\ cm

Hence, The distance from the center of the interference pattern will the first-order maximum appear is 50.38 cm.

User Corylus
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