Question

Consider the following network: proxy-cache On average there are 35 objects downloaded per second, and the average object size is 50,000 bits. What is the traffic intensity on the 2 Mbps access link?

a. 0.035
b. 0.007
c. 0.250
d. 0.875

Answer 1

(d) 0.875 erlangs

Step-by-step explanation:

In a digital network, the traffic intensity =
`\frac {aL}{R}`

where

a = average arrival rate of packets = 35 objects downloaded per second

L is the average packet length = 50,000 bits (e.g. in bits), and

R is the transmission rate = 2 Mbps = 2,000,000 bits per second

Traffic Intensity =
`\frac {aL}{R}=\frac {50000 X 35}{2000000}=\frac {1700000}{2000000}=0.875`