Question

Mutation at this locus changes one allele to the other (i.e. it does not create a new allele). If the rate of mutation from allele 1 to allele 2 is 0.00005 and the rate of mutation from allele 2 to allele 1 is 0.01, what is the equilibrium frequency of allele 2 (Give your answer to 5 decimal places)?

Answer 1

0.00498

Step-by-step explanation:

The equilibrium frequency can be calculated by the formula as follows:

qe = u/(u + v)

Here, qe is equilibrium frequency, u = 0.00005 = the forward mutation rate and v is the backward mutation rate = 0.01.

qe = 0.00005/(0.00005 + 0.01) =

qe = 0.00498.

Thus, the answer is 0.00498.